Two vibrating tuning forks produce progressiv | vedclass

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(C) The general equation for a progressive wave is $Y = A \sin(2\pi n t)$,where $n$ is the frequency.For the first tuning fork,$2\pi n_1 = 500\pi$,so

Vedclass · Accepted Answer

$180$

Vedclass · Answer

(C) The general equation for a progressive wave is $Y = A \sin(2\pi n t)$,where $n$ is the frequency.For the first tuning fork,$2\pi n_1 = 500\pi$,so $n_1 = 250 	ext{ Hz}$.For the second tuning fork,$2\pi n_2 = 506\pi$,so $n_2 = 253 	ext{ Hz}$.The number of beats per second is given by $|n_2 - n_1| = |253 - 250| = 3 	ext{ beats/second}$.To find the number of beats per minute,we multiply by $60$ seconds:$	ext{Beats per minute} = 3 	imes 60 = 180$.

Two vibrating tuning forks produce progressive waves given by $Y_1 = 4 \sin(500\pi t)$ and $Y_2 = 2 \sin(506\pi t)$. The number of beats produced per minute is:

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